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      <title>RabbitMQ中的消息顺序性 - 交互式测验</title>
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    <body>
      <div class="main-wrapper">
          <div class="quiz-container">
            <div class="quiz-header">
              <h1>RabbitMQ中的消息顺序性 - 交互式测验</h1>
              <p>检验你对文档内容的理解程度</p>
            </div>
            <div id="quiz-content">
                <div class="quiz-body">
                    <div class="progress-bar">
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      </div>

      <script>
        const quizData = [
  {
    "question": "根据文档，当系统中有多个消费者并行处理来自同一个队列的消息时，最容易引发哪种破坏消息顺序性的问题？",
    "options": [
      "消息持久化失败",
      "网络延迟",
      "并发处理导致处理完成顺序与发送顺序不一致",
      "交换机类型配置错误"
    ],
    "correctAnswerIndex": 2,
    "explanation": "文档明确指出，并发处理是消息顺序性的主要挑战之一。即使消息在队列中是按顺序排列的，多个消费者并行获取和处理它们，完成处理的顺序可能与消息的原始发送顺序不同，从而导致顺序被打乱。",
    "source": "文档中「消息顺序性的挑战」-「1. 并发处理」部分",
    "hint": "思考一下：当多个工人同时从一条传送带上取件加工时，他们完成工作的顺序会和物件上线的顺序完全一样吗？"
  },
  {
    "question": "为了确保与特定用户（如UserID为'123'）相关的所有操作消息都能按顺序处理，同时不影响其他用户的消息处理效率，哪种策略最为合适？",
    "options": [
      "使用单一消费者处理所有消息",
      "将所有消息广播到所有队列",
      "基于用户ID进行分区，确保同一用户ID的消息进入同一个队列/分区",
      "为每条消息设置事务"
    ],
    "correctAnswerIndex": 2,
    "explanation": "基于分区的顺序管理是解决此类问题的理想策略。通过使用用户ID等业务标识作为分区键，可以保证同一用户的所有消息被路由到同一个分区，并由同一个消费者处理，从而确保了分区内的消息顺序性，同时系统整体上还能并行处理不同分区的消息。",
    "source": "文档中「保证消息顺序性的策略」-「2. 基于分区的顺序管理」部分",
    "hint": "文档提到一种策略，它借鉴了Kafka等流处理系统的常见做法，通过消息的某个属性来路由消息。"
  },
  {
    "question": "在RabbitMQ中，哪种类型的交换机（Exchange）会将接收到的消息广播给所有绑定到它的队列，而忽略路由键（Routing Key）？",
    "options": [
      "直连交换机 (Direct Exchange)",
      "主题交换机 (Topic Exchange)",
      "扇出交换机 (Fanout Exchange)",
      "Headers交换机 (Headers Exchange)"
    ],
    "correctAnswerIndex": 2,
    "explanation": "扇出交换机（Fanout Exchange）的功能就是将接收到的所有消息路由到所有与其绑定的队列中，它不检查路由键。这种模式非常适合需要将消息广播给多个消费者的场景。",
    "source": "文档中「交换机和队列配置」-「2. 交换机的类型」部分",
    "hint": "想象一个“广播”场景，一条消息需要被所有订阅者无差别地接收。哪种交换机模型最符合这个描述？"
  },
  {
    "question": "文档中提到的“序列号机制”是如何帮助维持消息顺序的？",
    "options": [
      "序列号用于负载均衡，将消息均匀分配给消费者。",
      "序列号决定了消息在队列中的存储优先级。",
      "消费者可以根据消息中的序列号来重新排序或确认消息是否按序到达。",
      "生产者使用序列号来确保消息被持久化存储。"
    ],
    "correctAnswerIndex": 2,
    "explanation": "序列号机制是在应用层面控制顺序的一种策略。生产者为每条消息附加一个递增的序列号，消费者在接收到消息后，可以检查这个序列号，如果发现乱序（例如，处理完3号消息后收到了5号），就可以缓存5号消息，等待4号消息的到来，从而在处理层面恢复正确的顺序。",
    "source": "文档中「应用层的顺序控制」-「3.3. 序列号机制」部分",
    "hint": "这种机制允许消费者自己扮演“交通警察”的角色，来纠正可能发生的乱序情况。"
  },
  {
    "question": "根据文档，哪项是保证消息顺序性最直接、最简单，但可能会牺牲系统并发处理能力的方法？",
    "options": [
      "为每个队列配置多个消费者",
      "使用主题交换机进行复杂路由",
      "确保每个队列仅由一个消费者处理消息",
      "配置消息的自动删除属性"
    ],
    "correctAnswerIndex": 2,
    "explanation": "使用单一消费者是保证消息顺序最简单直接的方法。因为只有一个消费者从队列中按顺序取出并处理消息，所以自然就保证了处理顺序与发送顺序一致。然而，这种方法的缺点是显而易见的：它无法利用并发处理来提高吞吐量，可能成为系统的性能瓶颈。",
    "source": "文档中「保证消息顺序性的策略」-「1. 单一消费者」部分",
    "hint": "该策略虽然能完全保证顺序，但文档也提醒它“可能会降低系统的并发处理能力”。"
  },
  {
    "question": "消息处理失败时的重试机制为什么会成为消息顺序性的一大挑战？",
    "options": [
      "重试机制会增加系统的网络负载。",
      "失败的消息重投回队列后，其处理顺序可能落后于原本在其之后的新消息。",
      "重试机制要求交换机必须是持久化的。",
      "只有事务性消息才能被重试，这限制了其使用范围。"
    ],
    "correctAnswerIndex": 1,
    "explanation": "当一条消息（如消息B）处理失败并被重新放回队列时，此时消费者可能已经处理了后续的消息（如消息C）。当消息B被再次消费时，它的处理顺序就已经落后于消息C，从而破坏了原始的A-B-C顺序，变成了A-C-B。",
    "source": "文档中「消息顺序性的挑战」-「3. 重试机制」部分",
    "hint": "考虑一个场景：消息B处理失败了，而消息C在第一次尝试时就成功了。当B被重新尝试时，它和C的顺序会发生什么变化？"
  },
  {
    "question": "在配置RabbitMQ队列时，设置“持久性 (Durability)”属性的主要目的是什么？",
    "options": [
      "确保消息按发送顺序被消费",
      "限制队列中可以存放的消息数量",
      "确保在RabbitMQ服务重启或崩溃后，队列和其中的消息（如果消息也设置为持久化）不会丢失",
      "当没有消费者连接时自动删除队列"
    ],
    "correctAnswerIndex": 2,
    "explanation": "持久性是RabbitMQ可靠性机制的一部分。将队列（以及交换机和消息本身）设置为持久化，意味着它们的数据将被写入磁盘。这样，即使RabbitMQ服务器发生故障或重启，这些组件和数据也能被恢复，从而避免了数据丢失。虽然它有助于在恢复后保持顺序，但其主要目的在于保证数据的可靠性而非顺序性。",
    "source": "文档中「交换机和队列配置」-「5. 队列配置」部分",
    "hint": "这个配置项关系到当RabbitMQ服务意外停止后，你的队列和消息是否还能“幸存”。"
  }
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            const totalQuestions = quizData.length;
            const answeredCount = userAnswers.filter(a => a !== null).length;
            const wrongCount = answeredCount - correctCount;
            const skippedCount = totalQuestions - answeredCount;
            const accuracy = totalQuestions > 0 ? Math.round((correctCount / totalQuestions) * 100) : 0;
            const errorRate = totalQuestions > 0 ? Math.round((wrongCount / totalQuestions) * 100) : 0;

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                '<div class="score-card">' +
                '<h3>得分</h3>' +
                '<p>' + correctCount + ' / ' + totalQuestions + '</p>' +
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                '<div class="score-card">' +
                '<h3>正确率</h3>' +
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                '<div class="score-card">' +
                '<h3>错误率</h3>' +
                '<p>' + errorRate + '%</p>' +
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                '<div class="score-card score-details">' +
                '<table>' +
                '<tr><td>正确</td><td>' + correctCount + '</td></tr>' +
                '<tr><td>错误</td><td>' + wrongCount + '</td></tr>' +
                '<tr><td>未答</td><td>' + skippedCount + '</td></tr>' +
                '</table>' +
                '</div>' +
                '</div>' +
                '<div class="report-actions">' +
                '<button id="review-btn">回顾测验</button>' +
                '<button class="primary" onclick="location.reload()">再试一次</button>' +
                '</div>' +
                '</div>';

            let reportEl = document.querySelector('.final-score-container');
            if (reportEl) {
                reportEl.remove();
            }
            quizContentEl.insertAdjacentHTML('beforeend', finalScoreHtml);
            document.getElementById('review-btn').addEventListener('click', reviewQuiz);
        }

        function reviewQuiz() {
            const reportEl = document.querySelector('.final-score-container');
            if (reportEl) {
                reportEl.remove();
            }

            document.querySelector('.quiz-body').style.display = 'block';
            document.getElementById('quiz-footer').style.display = 'flex';
            
            currentQuestionIndex = 0;
            loadQuestion();
            updateNavigationButtons(); // Ensure nav buttons are correctly displayed
        }

        // Event Delegation for options
        optionsListEl.addEventListener('click', (event) => {
            if (event.target && event.target.matches('li.option-item')) {
                // Check if the question has already been answered
                if (userAnswers[currentQuestionIndex] === null) {
                    const selectedIndex = parseInt(event.target.dataset.index, 10);
                    selectOption(selectedIndex);
                }
            }
        });

        prevBtn.addEventListener('click', goToPreviousQuestion);
        nextBtn.addEventListener('click', goToNextQuestion);
        hintBtn.addEventListener('click', showHint);
        
        // 初始加载
        loadQuestion();
      </script>
    </body>
    </html>
  